Yangi Website ishga tushiriladi!!!

15-masala. Boshlang‘ich tayanch yechim (NW burchak) — 3×5 jadval

Jadval PDFda: talablar (110,90,120,80,150)(110,90,120,80,150), ta’minotlar (180,350,20)(180,350,20), xarajatlar (7,12,4,8,5),(1,8,6,5,3),(6,13,8,7,4)(7,12,4,8,5),(1,8,6,5,3),(6,13,8,7,4).

Moliya, Buxgalteriya, YaN

NW taqsimot

𝑥11=min⁡(180,110)=110⇒𝑎1=70, 𝑏1=0x11​=min(180,110)=110⇒a1​=70,b1​=0𝑥12=min⁡(70,90)=70⇒𝑎1=0, 𝑏2=20x12​=min(70,90)=70⇒a1​=0,b2​=20𝑥22=min⁡(350,20)=20⇒𝑎2=330, 𝑏2=0x22​=min(350,20)=20⇒a2​=330,b2​=0𝑥23=min⁡(330,120)=120⇒𝑎2=210, 𝑏3=0x23​=min(330,120)=120⇒a2​=210,b3​=0𝑥24=min⁡(210,80)=80⇒𝑎2=130, 𝑏4=0x24​=min(210,80)=80⇒a2​=130,b4​=0𝑥25=min⁡(130,150)=130⇒𝑎2=0, 𝑏5=20x25​=min(130,150)=130⇒a2​=0,b5​=20𝑥35=min⁡(20,20)=20⇒𝑎3=0, 𝑏5=0x35​=min(20,20)=20⇒a3​=0,b5​=0

Yakuniy reja

𝑋=(1107000002012080130000020)X=

​11000​70200​01200​0800​013020​

​

Umumiy xarajat

𝑍=7⋅110+12⋅70+8⋅20+6⋅120+5⋅80+3⋅130+4⋅20=3360Z=7⋅110+12⋅70+8⋅20+6⋅120+5⋅80+3⋅130+4⋅20=3360𝑍=3360Z=3360​Keyingi qadam (siz “davom et” deganingiz uchun mantiqan shu)

PDFda keyin 16–20 masalalar “optimal yechim” va 17-masala “potensiallar usuli” bor.

Moliya, Buxgalteriya, YaN

Agar davom desangiz, men 16-masalani:

1. boshlang‘ich tayanch yechim,
2. potensiallar 𝑢𝑖,𝑣𝑗ui​,vj​,
3. baholash Δ𝑖𝑗=𝑐𝑖𝑗−(𝑢𝑖+𝑣𝑗)Δij​=cij​−(ui​+vj​),
4. sikl bilan qayta taqsimlash
5. ketma-ketligida to‘liq optimalgacha chiqarib beraman.